62.6k views
25 votes
Write the equation of a circle whose diameter is 8 and whose center is (-8, -5)?

1 Answer

1 vote

if the diameter is 8, then its radius is half that or 4.


\textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-8}{ h},\stackrel{-5}{ k})\qquad \qquad radius=\stackrel{4}{ r} \\\\[-0.35em] ~\dotfill\\\\\ [x-(-8)]^2~~ + ~~[y-(-5)]^2~~ = ~~4^2\implies (x+8)^2+(y+5)^2=16

User Eftekhari
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories