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A bullet has a mass of 0.0042kg. The muzzle velocity of the bullet coming out of the barrel of the rifle is 993m/s. What is the KE of the bullet as it exits the gun barrel?

User Thibault J
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2 Answers

3 votes

Answer:

Explanation: the bullets travels with a kinetic energy

K.E=½MV²

K.E=½×0.0042×993²

K.E=0.0021×986049

K.E=2070.7029J

Step-by-step explanation:

User Roberto Hernandez
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5.3k points
2 votes

Answer: 2070.7029J

Explanation: the bullets travels with a kinetic energy

K.E=½MV²

K.E=½×0.0042×993²

K.E=0.0021×986049

K.E=2070.7029J

User Controlfreak
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4.8k points