Question

Fifty-six percent of Internet users have seen an online group come together to help a person or community solve a problem, whereas only 25% have left an online group because of unpleasant interaction. Develop a 95% confidence interval for the proportion of Internet users who say online groups have helped solve a problem.

Answer 1

Answer:confidence interval=[0.5257,0.5943]

Explanation:

Let the number of users be 800,

Let z=1.96

α=sqrt[(0.56x0.44)/800]

α=sqrt[0.2464/800]

α=sqrt(0.000308)

α=0.0175

Now calculating for the confidence interval

confidence interval=[(0.56-1.96x0.0175),(0.56+1.96x0.0175)]

confidence interval=[0.5257,0.5943]