Question

An electron is located in an electric field of magnitude 600 Newton's per coulomb. What is the magnitude of the electrostatic force acting in the electron?

Answer 1

The magnitude of the electrostatic force acting in the electron is
`9.6* 10^-^1^7N`.

Step-by-step explanation:

The relation between electric field, electric force and charge is given as

`F=eE`

Here E is electric field, F is the electric force and e is the electric charge on electron.

Given
`F=600N/C,\ e=-1.6*10^-^1^9C`.

Substitute the given values, we get

`F=-1.6*10^-^1^9C*600N/C`

The magnitude of force,

`|F|=9.6*10^-^1^7N`.

Thus, the magnitude of the electrostatic force acting in the electron is
`9.6* 10^-^1^7N`.

Answer 2

force on electron will be equal to
`9.6* 10^(-17)N`

Step-by-step explanation:

We have given magnitude of electric field E = 600 N/C

Charge on electron
`e=1.6* 10^(-19)C`

We have to find the electric force on the electron

Force in electric field is equal to
`F=qE`, here q is charge and E is electric field

So force will be equal to
`F=1.6* 10^(-19)* 600=960* 10^(-19)=9.6* 10^(-17)N`

So force on electron will be equal to
`9.6* 10^(-17)N`