Question

An ice-skater pushes off from a wall and skates 20 m across the ice. The skater did 2 J of work. If the skater used twice as much force, what would happen to the work done?

Answer 1

The work done will also be twice the former value; 4J

Step-by-step explanation:

Mathematically,

work = force x distance

W = F x d

Given;

W = 2J

d = 20m

F = ?

Hence

`2= F*20\\F=(2)/(20)\\F=0.1N`

When the force F is twice, we have

F = 2 x 0.1

F = 0.2N

Since the distance remains constant, the new work done becomes

W = 0.2 x 20

W = 4J