Question

Consider two identical 82-kg men who are eating identical meals and doing identical things except that one of them jogs for 30 min every day while the other watches TV. Determine the weight difference between the two in a month (30 days). An average 68 kg person consumes 540 Cath while jogging and 72 Cal/h while watching TV. The metabolizable energy content of 1 kg of fat is 33,100 kJ. The weight difference between the two in a month is kg.

Answer 1

1.07Kg

Step-by-step explanation:

-We assume that the two men's metabolic rates are identical.

-The jogger energy consumption is calculated as;

`\bigtriangleup E_(cons)=(540-72)* (0.5* 30)* (82)/(68)* 4.1868\\\\=35442.49\ kJ`

#The difference in weight of the two after one month is defined as:

`\bigtriangleup m=(\bigtriangleup E_(conc))/(e_(fat))\\\\=(35442.49)/(33100)\\\\=1.07 \ Kg`

Hence, the weight difference after 30 days is 1.07Kg