Question

The length of a rectangle is 6 cm longer than twice the width. If the length is increased by 9 cm and the width by 5 cm, the perimeter will be 160 cm. Find the dimensions of the original rectangle

Answer 1

Length is 46 cm and width is 20cm

Explanation:

An image was attached to provide the needed explanations

Answer 2

Original dimension = 46cm by 20cm

Explanation:

From the first sentence; L - 2W = 6---------1

from second sentence; (2)(L+9+W+5) = 160 = 2L +2W = 132--------2

Substitute L = 6 + 2W from eqn 1 into eqn 2

2(6+2W) + 2W = 132

6W = 120

W = 20

L = 6 + 2(20) = 46

Original dimension = 46cm by 20cm