Question

Saki is ice-staking to the left with velocity of 5 m/s. A steady breeze starts blowing. Causing saki to accelerate leftward at a constant rate of 1.5 m/s2. After 6s , what is saki velocity

Answer 1

Final velocity will be equal to 14 m/sec

Step-by-step explanation:

We have given initial velocity u = 5 m/sec

Constant acceleration is given
`a=1.5m/sec^2`

Time t = 6 sec

We have to find the final velocity

From first equation of motion
`v=u+at`, here v is final velocity, u is initial velocity , a is acceleration and t is time

So
`v=5+1.5* 6=14m/sec`

So equal final velocity will be equal to 14 m/sec