Question

For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 30 N acts on a certain object, the acceleration of the object is 5 m/s^2 . If the force is changed to 48 N , what will be the acceleration of the object?

Answer 1

The value of acceleration when force is changed to 48 N is =
`a_(2)` = 8
`(m)/(s^(2) )`

Explanation:

Force
`F_(1)` = 30 N

Acceleration
`a_(1)` = 5
`(m)/(s^(2) )`

Force
`F_(2)` = 48 N

Now Acceleration
`a_(2)` = ??

Given that the force acting on the object varies directly with the object's acceleration.

⇒ F ∝ a

⇒
`(F_(1) )/(a_(1) ) = (F_(2) )/(a_(2) )`

Put all the values in above formula we get

⇒
`(30)/(5) = (48)/(a_(2) )`

⇒
`a_(2)` = 8
`(m)/(s^(2) )`

This is the value of acceleration when force is changed to 48 N.