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*College readiness * i’m lost on how you are supposed it set it up

*College readiness * i’m lost on how you are supposed it set it up-example-1
User AveryLiu
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The mean grade on the quiz was 88.

Explanation:

We need to find the mean grade of the quiz using the information given.

The mean also known as the average is defined as the sum of data entries in a set divided by the number of entries in the data set.

The standard deviation gives the amount of variation or dispersion of data values present in a data set.

The given data are,

  • The standard deviation of the quiz, SD = 3.
  • The score 94 is exactly 2 standard deviations above the mean.

The above sentence represents that 94 is above the mean with 2 standard deviations.

⇒ 94 = Mean + 2 standard deviations.

We know the value for standard deviation. So substitute SD= 3 in the expression provided.

⇒ 94 = Mean + (2×3)

⇒ 94 = Mean + 6

To find mean, subtract 6 on both sides.

⇒ 94 -6 = Mean

⇒ Mean = 88

Therefore, the mean grade on the quiz was 88.

User Jolean
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