Answer:
Question 4:
m = 4 or -2
Question 5:
a = 5
b = -3
c= -19
Explanation:
1. TO PERFORM COMPLETING THE SQUARE PROCESS, the 1st thing i will do is to reduce the coefficient of x^2 to be 1. Then, I'll transfer the constant C to the right hand side of the equation, after that I'll square half the coefficient of x and then solve on from there.
2. Since the coefficient of m^2 is 1. I'll just add the square of half the coefficient of m to both sides. That is, I'll add up -9 to both sides of the equation.
3. I will make the coefficient of m^2 to be one. That is, I'll divide through the equation by 4.
4. 4m^2 - 8m = 32
Divide through by 4
m^2 - 8m/4 = 32/4
m^2 -2m = 8
Add the Square of half the coefficient of m to both sides
m^2 -2m + (-2/2)^2 = 8+ (-2/2)^2
Factorizing, we then have:
(m - 1)^2 = 9
Take the Square roots of both sides:
m - 1 = √9
m - 1 = plus or minus 3
m = 1 + 3
m = 4.
OR
m = 1-3
m = -2.
Therefore, m = 4 or -2
5. From the equation:
5x^2 -19 = 3x
5x^2 -3x - 19 = 0
a = 5
b = -3
c= -19
Math is fun