Answer:
see the explanation
Explanation:
Let
s ---> represent the number of silver beads
p ---> represent the number of purple beads.
we know that
On each necklace Gabby makes, there are 3 more purple beads than silver
beads.
so
The linear equation that model this situation is given by
![p=s+3](https://img.qammunity.org/2021/formulas/mathematics/middle-school/oycomfw871cpngup8rgn3t54yf89iq81p9.png)
To create a table, assume different values of s and solve for p
so
1) For s=1
substitute in the linear equation and solve for p
![p=1+3=4](https://img.qammunity.org/2021/formulas/mathematics/middle-school/4wi1m6nf1bn6ea1l2u2l9qgmn27vpmpcdf.png)
1) For s=2
substitute in the linear equation and solve for p
![p=2+3=5](https://img.qammunity.org/2021/formulas/mathematics/middle-school/x7z9mk738enklr2bfw8v3awnota5l9uk8r.png)
3) For s=3
substitute in the linear equation and solve for p
![p=3+3=6](https://img.qammunity.org/2021/formulas/mathematics/middle-school/wu4rohwebncwprd6u6391pazbpwttux9nh.png)
4) For s=4
substitute in the linear equation and solve for p
![p=4+3=7](https://img.qammunity.org/2021/formulas/mathematics/middle-school/4sbu4fw7dls4ge80uo1o23uzotx31pnjwu.png)
5) For s=5
substitute in the linear equation and solve for p
![p=5+3=8](https://img.qammunity.org/2021/formulas/mathematics/middle-school/s011h00beijbmytaurssn5mvdbrxhjniui.png)
therefore
The table is
![\left[\begin{array}{ccc}s&p\\1&4\\2&5\\3&6\\4&7\\5&8\end{array}\right]](https://img.qammunity.org/2021/formulas/mathematics/middle-school/oozm8f8gs8ixk1fw056rxlpys0zyop4918.png)