Question

A woman is 4 times as old as her son.9 years ago,the sum of their ages was 42.Find their present ages​

Answer 1

33

Explanation:

Answer 2

36 years

Explanation:

Let

Daughter = x

Mother = 3*x = 3x

6years ago? Daughter = x-6

Mother = 3x-6

Sum of ages at this time = (x-6) + (3x-6) = 36

x - 6 + 3x - 6 = 36

4x +(-12) = 36

4x = 36 + 12

4x = 48

x = 48/4 ; 12 years old.

Mother = 12*3= 36 years old.

Check. 12–6= 6;

36–6=30

30+6=36 years.