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Logan ran 3 5/12 miles on Friday. And 2 3/8 miles on Saturday. He rode his bike 9 5/6 miles on Sunday. How much father did he ride his bike than run

User Sheila
by
5.0k points

2 Answers

0 votes

Answer:

4 1/24

Explanation:

First you need have a common denominator:

3 5/12 = 3 10/24

2 3/8 = 2 9/24

9 5/6 = 9 20/24

You add both of the miles for running:

3 10/24 + 2 9/24 = 5 19/24

Now subtract the miles for running and the miles of the bike ride:

9 20/24 - 5 19/24 = 4 1/24

Answer: 4 1/24

User Coykto
by
4.6k points
3 votes

Answer:he rode 4 2/48 miles farther while biking.

Explanation:

Logan ran 3 5/12 miles on Friday. Converting 3 5/12 miles to improper fraction, it becomes 41/12 miles.

He ran 2 3/8 miles on Saturday. Converting 2 3/8 miles to improper fraction, it becomes 19/8 miles.

Total distance covered while running is

41/12 + 19/8 = 278/48

He rode his bike 9 5/6 miles on Sunday. Converting 9 5/6 to improper fraction, it becomes 59/6 miles.

The difference between the distance covered while riding the bike and while running is

59/6 - 278/48 = 194/48 miles

Converting to mixed fraction, it becomes

4 2/48 miles

User Partoa
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4.8k points