Answer:
The distance travel before stopping is 1.84 m
Step-by-step explanation:
Given :
coefficient of kinetic friction
![\mu_(k) = 0.250](https://img.qammunity.org/2021/formulas/physics/college/pehr2hb2ckkmxih8x4vpwbwmcmgaht7234.png)
Zak's speed
![v = 3 (m)/(s)](https://img.qammunity.org/2021/formulas/physics/college/8m7a8miaw6194gb348jgwqr9nwliqwynqb.png)
Gravitational acceleration
![(m)/(s^(2) )](https://img.qammunity.org/2021/formulas/mathematics/college/jiy2qz9qmtkzqbj8aqh0n24nt4jr0ceyzk.png)
Work done by frictional force is given by,
![W = \Delta K](https://img.qammunity.org/2021/formulas/physics/college/x95akgue07bp1dly5tn4mjpw5z2a41t45d.png)
![\mu _(k) mg d = (1)/(2) m v^(2)](https://img.qammunity.org/2021/formulas/physics/college/uq0mo5cts3b53lua73dkr5us9tn9gebzbe.png)
![d = (v^(2) )/(2 g \mu _(k) )](https://img.qammunity.org/2021/formulas/physics/college/ag4nfocmn0pia59a9rxzd4cl3k4vju33sl.png)
![d = (9)/(2 * 9.8 * 0.250)](https://img.qammunity.org/2021/formulas/physics/college/kimqij69dtev2n9uajff9n4bry6sg03d9u.png)
m
Therefore, the distance travel before stopping is 1.84 m