Answer:
0.0222 mol KCl
Step-by-step explanation:
2 KClO3 (s) 2 KCl (s) + 3 O2 (g)
2.73 g x mol
x g KCl = 2.73 g KClO3 x[ (1 mol KClO3)/ (122.5 g KClO3) ] x [(2 mol KCl)/ (2 mol KClO3)]
x g KCl = 0.0222 mol KCl
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