Question

Two vehicles approach an intersection: a truck moving eastbound at 16.0 m/s and an SUV moving southbound at 20.0 m/s. Suppose that the x-axis is directed eastward and the y-axis is directed northward. Find the magnitude of the velocity vector of the truck relative to the SUV.

Answer 1

The value of magnitude of the velocity vector of the truck relative to the SUV
`V_(xy)= 25.62 (m)/(sec)`

Step-by-step explanation:

Velocity of the truck
`V_(x)` = 16
`(m)/(s)`

Velocity of the SUV
`V_(y)` = - 20
`(m)/(s)`

The magnitude of the velocity vector of the truck relative to the SUV is

`V_(xy) =\sqrt{ V_(x) ^(2) + V_(y)^(2)}`

Put the value of
`V_(x)` &
`V_(y)` in the above equation we get

`V_(xy) = \sqrt{(16)^(2) + (-20)^(2)}`

`V_(xy) = √(656)`

`V_(xy)= 25.62 (m)/(sec)`

This is the value of magnitude of the velocity vector of the truck relative to the SUV.