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A Jack-In-The-Box is built around a spring with a spring constant of 70 N/m. How hard does the

spring push when you compress it from 40 cm long down to 15 cm long?

User Mehmed
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1 Answer

6 votes

Hooke's Law Formula:

F = k * x

•F = Force

•K = Spring Constant

•X = spring variation

Answer:

F = ?

K = 70 N/m

X = 40cm - 15cm (ending length - starting length).

But we need to change 'cm' to 'm', so we will divide the result of X by 100.

X= 25/100 → 0.25m

F = 0.25 * 70

F = 17.5 N

- mbsilvaf

User DotNetDublin
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