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5 votes
Consider the given function.

f(x) = x^2 -14x -72
What are the zeros and axis of symmetry for the graph of the function?
A. 
zeros: x = -9 and x = -8;
axis of symmetry: x = -7
B. 
zeros: x = -18 and x = 4;
axis of symmetry: x = -7
C. 
zeros: x = 9 and x = 8;
axis of symmetry: x = 7
D. 
zeros: x = -4 and x = 18;
axis of symmetry: x = 7

2 Answers

3 votes

Answer:

D

Explanation:

User Mikka
by
4.7k points
7 votes

Answer:

D)

Explanation:

f(x) = x^2 -14x -72

0=x^2 - 14x-72

0=x^2 - 18x+4x-72

0=x(x-18)+4(x-18)

0=(x-18)(x+4)

x-18=0 or x+4=0

x1=18 or x2=-4

asis of symmetry: x=(x1+x2)/2

x=(18+(-4))/2

x=14/2

x=7

User Semmel
by
5.9k points