Question

A charge of 9.0x10^-5 C is placed in an electric field with a strength of 4.0x10^4 N/C. What is the electrical force acting on the charge

Answer 1

The force is 3.6 Newtons.

Step-by-step explanation:

The given data is

Charge (q)=
`9.0 * 10^(-5)C`

Electric field (E)=
`4.0 * 10^(4) N/C`

Now the formula for electric force is

Force (F) = q E

So ,

`F = 9.0 * 10^(-5)C * 4.0 * 10^(4) N/C`

Or

`F = 3.6 N`

Thus the force is 3.6 Newtons