Question

Consider an NACA 2412 airfoil with a 2-m chord in an airstream with a velocity of 50 m/s at standard sea level conditions. If the lift per unit span is 1353 N/m, what is the angle of attac

Answer 1

4°

Step-by-step explanation:

Given,

chord in the airstream, c = 2 m

speed, v = 50 m/s

lift per unit span = 1353 N/m

density of air, ρ = 1.225 kg/m³

Lift,
`L = c_L * (1)/(2) \rho v^2(c * s)`

`(L)/(s)=c_L * (1)/(2) \rho v^2* c`

`50=c_L * 0.5* 1.225* 50^2* 2`

`c_L = 0.44`

From the plot of c_L and angle of attack

Angle of attack is equal to 4°