Question

Gases [9A.R, 9B.S]:Question 10
What volume does 3.0 mol of a gas occupy at 2 atm and 10 °C

Answer 1

The volume is 35L

Step-by-step explanation:

We use the formula PV=nRT.We convert the temperature in Celsius into Kelvin: 0°C=273K---> 10°C=273+10= 283K

PV=nRT ---> V=(nRT)/P

V=(3 mol x 0,082 l atm/K mol x 283K) / 2 atm

V=34, 809 L