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Complete Question:
A tightrope walker stands in the middle of a high wire that is stretched 10 m between the two platforms at the ends of the wire. The tightrope walker bounces up and down, creating a standing wave with a single antinode and a period of 2.0 s.
a. What is the wavelength of the wire wave been produced?
b. What is the frequency of this wave?
c. What is the speed of this wave?
Answer:
a. Wavelength of the wire wave been produced = 20m
b. Frequency of this wave = 0.5Hz
c. Speed of this wave = 10m/s
Step-by-step explanation:
a. Wavelength of the wire wave been produced is calculated as
2 × L
Where L is the length of the wire
Wavelength = 2 × 10m
Wavelength = 20m
b. Frequency of this wave can be calculated as:
1÷T
Where T = period = 2.0s
Frequency = 1÷2.0s
Frequency = 0.5Hz
c. Speed of this wave is calculated as
Wavelength × Frequency
Wavelength = 20m
Frequency = 0.5Hz
Speed of the wave = 20m × 0.5Hz
= 10m/s