Question

The following figure shows AABC with side lengths to the nearest tenth.

C
48
6
71
A
B
Find AB in AABC.
Round to the nearest tenth.

Answer 1

AB = 4.7 to the nearest tenth

Explanation:

Usine the Sine Rule:

6/sin71 = AB/sin48

AB = (6 * sin48)/ sin71

= 4.716