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A box of crayons contains 3 reds, 5 blues and 2 greens. If a child chooses a crayon at random,find the probability of choosing a red crayon

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ANSWER IS=3/10

NUMBER OF RED CRAYONS=3

NUMBER OF BLUE CRAYONS=5

NUMBER OF GREEN CRAYONS=2

PROABABILITY = FAVORABLE OUTCOMES/TOTAL NUMBER OF OUTCOMES

FAVORABLE OUTCOMES=3

TOTAL NUMBER OF OUTCOMES=10

ANSWER=3/10

User Thomas Ingham
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Answer:

100

Explanation:

3 x 5 x 2 30 divided by 3 = 10 x 10 = 100

User BlueBoy
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