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If the equation of a circle is (x - 2)2 + (y - 6)2 = 4, it passes through point ______.

1 Answer

2 votes

Answer:


(4,6),(2,8),(0,6),(2,4) (the list goes on)

Explanation:

So the equation


(x - 2)^2 + (y - 6)^2 = 4

Let's try to graph it out (I won't actually graph it out here as I can't but try to follow along)

The first thing we notice from the equations is that the circle has a radius of 2, so draw a circle from the origin that has a radius of two, our most notible points at this stage are


(2,0),(0,2),(-2,0),(0,-2)

Now applying the transformation of 2 to the right and six up the new points become


(4,6),(2,8),(0,6),(2,4)

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