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Simplified (4x3 - 5x2 + 3x) + (-2x3 - x2 + 6x)

User Macabeus
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1 Answer

5 votes

Answer:

Answer is imaginary roots

Explanation:


({4x}^(3) - {5x}^(2) + 3x) + ( - {2x}^(3) - {x}^(2) + 6x) \\ 2 {x}^(3) - 6 {x}^(2) + 9x = 0 \\ dividing \: by \: x \\ 2 {x}^(2) - 6x + 9 = 0 \\ dividin g\: by \: 2 \\ {x}^(2) - 3x + (9)/(2) = 0 \\ shifting \: the \: constant \: term \: on \: right \: side \\ {x}^(2) - 3x = - (9)/(2) \\ adding \: (1)/(2) * (coefficient \: of \: x) \: whole \: square \\

On solving the above mentioned equation we get some imaginary values.

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User Picklepick
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