Given that the two functions are
and
![g(x)=5x-1](https://img.qammunity.org/2021/formulas/mathematics/middle-school/so1puskhf0rr8y7o9jj5f9040kfr9qkio1.png)
We need to determine the value of
![(f(x))/(g(x))](https://img.qammunity.org/2021/formulas/mathematics/middle-school/vdc289tor0g1si3wvlto2k4obvaqtw7kkm.png)
The value of
:
To determine the value of
, let us substitute the functions
and
in
![(f(x))/(g(x))](https://img.qammunity.org/2021/formulas/mathematics/middle-school/vdc289tor0g1si3wvlto2k4obvaqtw7kkm.png)
Thus, we get;
![(f(x))/(g(x))=(5x^3-x^2-60x+12)/(5x-1)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/8gusc42pif386kig4sth5n2gi7w853t258.png)
Let us group the terms in the numerator.
Thus, we get;
![(f(x))/(g(x))=((5x^3-x^2)-(60x-12))/(5x-1)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/y634jo51qqsw48u9i96hngx6joysd5ncmu.png)
Factoring out the common terms from each group, we get;
![(f(x))/(g(x))=(x^2(5x-1)-12(5x-1))/(5x-1)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/26u3ajjrl4somqv64dk3aphrrg4rhwkbz5.png)
Factoring out the term (5x - 1), we have;
![(f(x))/(g(x))=((x^2-12)(5x-1))/(5x-1)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/hnkf7kik4bnidu2o4mf0ylrrymztmpxe1q.png)
Cancelling the common terms, we get;
![(f(x))/(g(x))=x^2-12](https://img.qammunity.org/2021/formulas/mathematics/middle-school/nhzofsvfymrjmcgujiuj5ha8drtuhzq2pt.png)
Thus, the value of
is
![x^2-12](https://img.qammunity.org/2021/formulas/mathematics/middle-school/21g5i0herinmqjraptmk7w8bm1rl1i8wqe.png)
Hence, Option A is the correct answer.