Answer:
Valency of H can not be equal to 2.
Step-by-step explanation:
Let's consider a cyclic ether e.g. tetrahydropyran.
In this cyclic structure, valency of all constituent atoms e.g. C, H and O are satisfied. So, it is a potentially stable structure. Hence, cyclic ether exist.
If we replace O in tertrahydropyran by a -OH group and tries to embed it into ring then it requires valency of H equal to 2. This is potentially not possible because H has only one valence electron and no energetically available vacant orbital.
So, cyclic alcohol structure with -OH group embedded in the ring would give an unstable structure. Hence, it does not exist.