Answer:
±
![√(22) -3](https://img.qammunity.org/2021/formulas/mathematics/high-school/s95givvz2lffe72mqovw65fvppctx5ry1f.png)
Explanation:
we would need to first separate the -13 to complete the square. To do that we divide 6 from the 6q by 2, which is 3. We then square the 3 to get positive 9. We separate the equation to become
![q^2+6q+9-22=0](https://img.qammunity.org/2021/formulas/mathematics/high-school/i876cebwvndvdam0d276mxaoy3x98zc6z6.png)
since 9 - 22 is the same as -13
We can then reverse factor and get the equation to the form of:
![(q+3)^2-22=0](https://img.qammunity.org/2021/formulas/mathematics/high-school/7d608lb637k0krbbaexnmkn47cw0sww0cr.png)
Moving the -22 to the other side yields
![(q+3)^2=22](https://img.qammunity.org/2021/formulas/mathematics/high-school/7lkbvw0e2wkw1lo7nvcy0inlcsz4zrq6me.png)
Taking the square root then isolating the q gives us the answers:
±
![√(22) -3](https://img.qammunity.org/2021/formulas/mathematics/high-school/s95givvz2lffe72mqovw65fvppctx5ry1f.png)