Answer:
Shortest distance=|AC|/
.
Kindly find the attached for the figure
Explanation:
This problem can be addressed using right-angled,
Let have right angle triangle with the shortest distance=hypotenuse;
hypotenuse=|AC|
using pythagoras theorem, we have
|AC|^2=|AB|^2+|BC|^2
Let |AB|=|BC|
|AC|^2=2|AB|^2
|AB|=|AC|/
![\sqrt[2]{2}](https://img.qammunity.org/2021/formulas/mathematics/college/uik0xo2lujfiqnb5llbsgi5vt7n45p3dqg.png)
Shortest distance=|AC|/
![\sqrt[2]{2}](https://img.qammunity.org/2021/formulas/mathematics/college/uik0xo2lujfiqnb5llbsgi5vt7n45p3dqg.png)