Answer:
161376 kJ
Step-by-step explanation:
The equation for standard Gibbs energy free energy for a reaction is -
ΔG⁰ = ΔH⁰ - TΔS⁰
The values of ΔH⁰, T and ΔS⁰ are given in the question as
ΔH⁰ = -2256 kJ
T = 298 K
ΔS⁰ = -549.1 kJ
So, putting these values in the above equation we get
ΔG⁰ = -2256 - (-549.1 × 298)
ΔG⁰ = -2256 + 163631.8 = 161375.8 ≈ 161376 kJ
Thus, the standard Gibbs free energy for the reaction mentioned in the question will be 161376 kJ.