Question

find the point, M, that divides segment AB into a ratio of 5:2 if A is at (1,2) and B is at (8, 16).​

Answer 1

Explanation:

A(1,2) ---->(x1,y1)

B(8,16) ----->(x2,y2)

m:n = 5:2

`M((x_(2)m+x_(1))/(m+n),y_(2)m+y_(1)}{m+n})\\\\=M((5*8+2*1)/(5+2),(5*16+2*2)/(5+2))\\\\=M((40+2)/(7),(80+4)/(7))\\\\=M((42)/(7){,(84)/(7))\\\\=M(6,12)`