Question

Forrest drops a rock from a bridge to the water below. The rock entered the water at a speed of 19.6 m/s. How long did it take the pebble to reach the water from the bridge? [s=d/t]

Answer 1

It took the rock 2 seconds to get to the water from the bridge.

Step-by-step explanation:

Since Forrest drops the rock, it means its initial velocity is zero, and because it is freely falling under the influence of gravity, after time
`t` it will gain a velocity
`v` of

`v = gt`,

solving for
`t` we get:

`t = (v)/(g).`

Since in our case the velocity the rock gained was
`v= 19.6m/s` and the acceleration due to gravity is
`g =9.8m/s^2`, we have

`t = (19.6m/s)/(9.8ms^(-2))`

`\boxed{t =2s.}`

Thus, the time took the rock to reach the water from the bridge was 2 seconds.