Question

Two metal plates 15mm apart have a potential difference of 750v between them. The force on a small charged sphere placed between the plates is 1.2x10^-7 . Calculate the strength of the electric field between the plates

Answer 1

50,000 V/m

Step-by-step explanation:

The electric field between two charged metal plates is uniform.

The relationship between potential difference and electric field strength for a uniform field is given by the equation

`\Delta V=Ed`

where

`\Delta V` is the potential difference

E is the magnitude of the electric field

d is the distance between the plates

In this problem, we have:

`\Delta V=750 V` is the potential difference between the plates

d = 15 mm = 0.015 m is the distance between the plates

Therefore, rearranging the equation we find the strength of the electric field:

`E=(\Delta V)/(d)=(750)/(0.015)=50,000 V/m`