Question

Mass (kg) 4.0

Applied Force (N) 20.0
Surface Friction 0
On the simulation click on the last circle of the velocity time graph this should be at time = 5.0 seconds. What is the velocity of the box at 5 seconds?

Answer 1

25 m/s

Step-by-step explanation:

First of all, we can find the acceleration the object by using Newton's second law of motion:

`F=ma`

where

F = 20.0 N is the net force applied on the object

m = 4.0 kg is the mass of the object

a is its acceleration

Solving for a, we find

`a=(F)/(m)=(20)/(4)=5.0 m/s^2`

Now we know that the motion of the object is a uniformly accelerated motion, so we can find its final velocity by using the following suvat equation:

`v=u+at`

where

v is the final velocity

u = 0 is the initial velocity

`a=5.0 m/s^2` is the acceleration

t = 5 s is the time

By substituting,

`v=0+(5.0)(5)=25 m/s`