Domain questions are basically validity checks. Since you cannot have a negative number in a square root without creating an imaginary number, that takes out the bottom two.
A quick tip: substitute the value for x. If the equation is valid (no imaginary numbers, not dividing by 0, etc, that function has the given domain.
ex:
![y = √(x-11) +5\\y = √(-11 -11) + 5\\y = √(-22) + 5](https://img.qammunity.org/2021/formulas/mathematics/high-school/poy65ov8eaz8had6muiwr39tsqx6peimv4.png)
Negative square roots lead to imaginary numbers so this is not the domain for this problem. The Domain for this one is
since that is the lowest possible value of x you can have that is valid.
To answer your question, since I assume you are pressed for time,
![y = √(x + 11) + 5\\y = √(-11 + 11) + 5\\y = √(0) +5\\y = 0 + 5\\y = 5](https://img.qammunity.org/2021/formulas/mathematics/high-school/xjaz5lq3xa1txvru09fpqylfv79mlrvwae.png)
so the first one is the function that has the given domain.