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How many moles of Al(CN)3 are in 227 g of the compound?
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How many moles of Al(CN)3 are in 227 g of the compound?

User Ramses
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Answer: 2.16 moles Al(CN)3

Explanation: To find the number of moles of Al( CN)3 we will use stoichiometry which is the relationship of mole with molar mass.

227 g Al(CN)3 x 1 mole Al(CN)3 / 105 g Al(CN)3

= 2.16 moles Al(CN)3

Cancel out the unit of grams Al(CN)3 and the remaining unit is in moles Al(CN)3.

How many moles of Al(CN)3 are in 227 g of the compound?-example-1
User Russell Newquist
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