Question

Please answer this Calculus 1 question I really need help will give Braniliest five stars!

Answer 1

Explanation:

Let's first subtitute
`e^(7xcosx)` with
`g(x)`

This will turn the problem into

`y = e^(g(x))`

Using the chain rule, we will find that the derivative of this function,
`y'`, is represented by the following:

`y' = g'(x)e^(g(x))`

We know what
`g(x)` is in this case, but we need to find
`g'(x)`.

This can be done with the product rule:

`g'(x) = 7cos(x) - 7xsin(x)`

Plugging these functions back into the original subtitution will give you the final answer:

`y' = (7cos(x) - 7xsin(x))e^(7xcosx)`