1 Answer

Shique · Answer 1 · 2021-12-12T22:24:04+0000

$y = x -2, x\geq 1$

Explanation:

In the question given correct parameter is - 2)
$y = x -2, x\geq 1$

Method -

x= t^2 + 1 ........................(1)

y = t^2 - 1 ..........................(2)

Let's solve the equation 1,

⇒
x = t^2 +1

⇒
t^2 = x - 1

$y =t^2 - 1 \\y = x -1 -1\\y = x - 2$

Here we got the y parameter as
y = x -2

So the option no .2 is the correct option 2)
$y = x -2, x\geq 1$

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