Question

A uniformly charged conducting plate with area A has a total charge Q which is positive. Consider a cross-sectional view of the plane and the electric field lines due to the charge on the plane. E E +Q + + + + + + + + + + + P Find the magnitude of the field at point P, which is a distance a from the plate. Assume that a is very small when compared to the dimensions of the plate, such that edge effects

Answer 1

Complete Question

The complete question is shown on the first uploaded image

Answer:

The correct answer is option 9

Step-by-step explanation:

The objective of this question i to obtain the magnitude of the electric field

We are told from the question that

The area is A

The magnitude of the total charge is Q

Generally the surface charge density is mathematically represented as

`\sigma = (Q)/(A)`

Now the electric field for a uniform conducting plate is mathematically represented as

`E = (|\sigma| )/(2\epsilon_o)`

Now substituting the formula above for
`\sigma`

`E = (Q)/(2\epsilon_o A)`