Answer:
![3.14r^2(h-(1)/(3)h_1)](https://img.qammunity.org/2021/formulas/mathematics/high-school/poyuxfkci2c9ayqeq2382jfttnwulcgsyu.png)
Explanation:
Let h be the cylinders height and r the radius.
-The volume of a cylinder is calculated as:
![V=\pi r^2h](https://img.qammunity.org/2021/formulas/mathematics/college/1l8ozclpk7wnbc3iifytlwq8czg1is3e65.png)
-Since the cone is within the cylinder, it has the same radius as the cylinder.
-Let
be the height of the cone.
-The area of a cone is calculated as;
![V=\pi r^2 (h)/(3)\\\\=(1)/(3)\pi r^2h_1](https://img.qammunity.org/2021/formulas/mathematics/high-school/kbakath8hi998o57698f4c1g2hchb3dze7.png)
The volume of the solid section of the cylinder is calculated by subtracting the cone's volume from the cylinders:
![V=V_(cy)-V_(co)\\\\=\pi r^2h-(1)/(3)\pi r^2 h_1, \pi=3.14\\\\=3.14r^2(h-(1)/(3)h_1)](https://img.qammunity.org/2021/formulas/mathematics/high-school/w7nce7rj6qua5kfxrqup8lcff0vhijdsxy.png)
Hence, the approximate area of the solid portion is
![3.14r^2(h-(1)/(3)h_1)](https://img.qammunity.org/2021/formulas/mathematics/high-school/poyuxfkci2c9ayqeq2382jfttnwulcgsyu.png)