53,380 was the average last year .
Explanation:
Here we have , So far this year, the average monthly revenue at Lexington Times is 50,711. That is 5% less than the monthly average was last year. We need to find that What was the average last year . Let's find out:
Let the monthly average was last year be x , According to question the average monthly revenue at Lexington Times is 50,711 but , That is 5% less than the monthly average was last year . Following equation for above scenario is :
⇒
![x-(5(x))/(100)=50711](https://img.qammunity.org/2021/formulas/mathematics/middle-school/a99ssu2za3wbi94tr1h3k293v1xqt5ncde.png)
⇒
![(100x-5x)/(100)=50711](https://img.qammunity.org/2021/formulas/mathematics/middle-school/8h3aoxh98gzk121sb7zp8xoliq5yur0mbu.png)
⇒
![(95x)/(100)=50711](https://img.qammunity.org/2021/formulas/mathematics/middle-school/8be4wvlkxwalk9y2usz5bljus19z2fkby3.png)
⇒
![(95x(100))/(100(95))=(50711(100))/(95)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/9orkakhj1tfajfn7kjmq13e5lt5prkxrpr.png)
⇒
![x=(50711(100))/(95)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/vpm59f7ix9yeqvdz3k583skj7naftokf2h.png)
⇒
![x=53380](https://img.qammunity.org/2021/formulas/mathematics/middle-school/4la2nvkpn5lz691h7ng2rv6s81a75nk1d1.png)
Therefore , 53,380 was the average last year .