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Consider these equations: 2S (s) + 3O2 (g)→2SO3 (g), ΔH = −792 kJ 2S (s) + 2O2 (g)→2SO2 (g), ΔH = −594 kJ 2SO2 (g) + O2 (g)→2SO3 (g), ΔH =? What is the missing ΔH? a. −294 kJ b. −198 kJ c. +198 kJ d. +294
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5 votes
Consider these equations:

2S (s) + 3O2 (g)→2SO3 (g), ΔH = −792 kJ
2S (s) + 2O2 (g)→2SO2 (g), ΔH = −594 kJ
2SO2 (g) + O2 (g)→2SO3 (g), ΔH =?

What is the missing ΔH?

a. −294 kJ
b. −198 kJ
c. +198 kJ
d. +294 kJ

User Luis Machuca
by
8.5k points

2 Answers

9 votes
The answer is a look at the solutions of G how they line up with each other we know so much about him
User Alex Monthy
by
8.2k points
2 votes

Answer: (B) −198 kJ.

User Kalpa Gunarathna
by
7.3k points
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