Question

The Great Pyramid of Giza was constructed as a regular pyramid with a square base. It was built with an approximate volume of 2,592,276 cubic meters and a height of 146.5 meters. What was the length of one side of its base, to the nearest meter?7377133230

Answer 1

l = 133.02m

l = 133m (Appropriately)

Explanation:

The volume of a Square Base Pyramid is expressed as :

V = Bh

Where

B = Base Area (That Square)

h = Height of the Pyramid.

To solve for the Base Area, we use the area of a square, which is eqa to (l * l = l^2)

Having this Understanding, Let's solve on proper now.

From the Question:

V = 2,592,276 cubic meters

h = 146.5 meters.

Base Area isn't given.

Therefore:

V= Bh

B= V/h

B= 2,592,276 / 146.5

B= 17694.72 m^2

Since we've gotten the value for the Base Area, let's solve for the length of one side of the base.

Base Area (B) = l^2

B = l^2

Recall that B= 17694.72 m^2

Therefore:

l^2 = 17694.72 m^2

l = √ 17694.72 m^2

l = 133.02 m

l = 133 m (Approximately)

Answer 2

The answer to your question is length of a side = 133 m

Explanation:

Data

Total volume = 2,592,276 m³

height = 146.5 m

length = x

Process

1.- Calculate the area of the base

The Volume of a pyramid = Area of the base x height

-Solve for area of the base

Area of the base = Volume of a pyramid/height

-Substitution

Area of the base = 2,592,276 / 146.5

-Result

Area of the base = 17694.7167 m²

2.- Calculate the length of one side

Area of the base = side x side

Area of the base = side²

side² = 17694.7167 m²

side = √17694.7167 m²

side = 133 m