Answer:
1 and 7
Step-by-step explanation:
You haven't given the NMR spectrum. I assume the VOC is 3-methylbutyl 2-methylbutanoate (below).
The doublets are the isopropyl methyl groups (1) and the 2-methyl group (7)
Group 1 should appear as a 6H doublet (J β 7 Hz) near 0.9 ppm.
Group 7 should appear as a 3H doublet (J β 7 Hz) at about 1.1 ppm (pulled slightly downfield by the carbonyl group).
A simulated NMR spectrum of the CHβ region is shown below. The triplet in the spectrum is the terminal methyl group (8).