Question

What is the volume of 6.7 mol of an ideal gas at 145 kPa and 23° Celsius

Answer 1

The volume is 113,72 L

Step-by-step explanation:

We use the formula PV=nRT. We convert the unit of pressure in kPa into atm; and the temperature in Celsius into Kelvin

101,325kPa----1atm

145kPa-------x=(145kPax 1 atm)/101,325kPa=1, 43 atm

0°C= 273K--> 23+273=296K

PV=nRT---->V=(nRT)/P

V=(6,7 mol x 0,082 l atm/K mol x 296K)/1, 43 atm= 113,72 L