Question

You have determined a GC spectrum for your sample oil. You find 3 peaks. From determination of peak area, you find that the percent compositions represented by the peaks are: peak A is 66 percent , peak B is 22.66 percent, and peak C is 11.33 percent. The M.W. of your diene is 136 g/m. How many grams of Maleic Anhydride (M.W. 98 g/m) will you use to react with your 2.5g sample of crude diene?

Answer 1

1.19 g

Step-by-step explanation:

Given that:

Molecular weight of diene
`M.W_d =`136 g/mol

Molecular weight of Maleic Anhydride
`M.W_(m.a)=`96 g/mol

Mass of crude diene = 2.5 g

Percent of Composition for Peak A = 66%

Percent of Composition for Peak B = 22.66%

Percent of Composition for Peak C = 11.33%

Let us determine the amount of diene in the sample;

So, using
`A_d` to represent the amount of diene; we have :

`A_d` =
`m*P_a`

`A_d` =
`2.5 *(66)/(100)`

`A_d` = 1.65 g

Using the limiting reagent equation to determine the amount of Maleic Anhydride
`A_(ma)`

`A_(ma)` =
`A_d`
`* (1mole diene)/(M.W_d) *(M.W_(m.a))/(1 mole of maleic anhydride)`

`A_(ma)` =
`1.65 * (1 mole)/(136)*(98)/(1 mole)`

`A_(ma)` = 1.19 g

The grams of Maleic Anhydride used to react with 2.5 g sample of crude diene = 1.19 g