Question

Captain Tiffany has a ship, the H.M.S. Khan. The ship is two furlongs from the dread pirate Omar and his merciless band of thieves.The Captain has probability of 1/2 of hitting the pirate ship. The pirate only has one good eye, so he hits the Captain's ship with probability 2/7.If both fire their cannons at the same time, what is the probability that both the pirate and the Captain hit each other's ships

Answer 1

The answer is 1/7

Explanation:

Answer 2

0.1428 is the probability that both the pirate and the Captain hit each other's ships.

Explanation:

We are given the following in the question:

Probability of captain hitting pirate's ship =

`P(C)=(1)/(2)`

Probability of pirate hitting captain's ship =

`P(P) = (2)/(7)`

If events are independent events, we can write:

`P(A\cap B) =P(A)* P(B)`

We have to evaluate the probability that both the pirate and the Captain hit each other's ships.

`P(C\cap P) = P(C) * P(P)\\\\P(C\cap P) = (1)/(2)* (2)/(7) = (1)/(7) = 0.1428`

0.1428 is the probability that both the pirate and the Captain hit each other's ships.