Question

2 3 ​ y−3+ 3 5 ​ zstart fraction, 3, divided by, 2, end fraction, y, minus, 3, plus, start fraction, 5, divided by, 3, end fraction, z when y = 6 y=6y, equals, 6 and z = 3 z=3

Answer 1

11

Explanation:

We are required to evaluate the value of the expression
`(3)/(2)y-3+(5)/(3)z` when y=6 and z=3.

`(3)/(2)y-3+(5)/(3)z`

We simply substitute the values y=6 and z=3.

`((3)/(2)X6)-3+((5)/(3)X3)\\=(18)/(2)-3+(15)/(3)\\=9-3+5\\=6+5\\=11`

The value of the expression given y=6 and z=3 is 11.